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Hooke's law sim

Load 50 g masses onto a spring and watch it stretch the same 12.3 mm every time.

Forces: springs and extension · covers the IGCSE, GCSE, O-Level topic

Live, not a video. Anyone can unlock 2 figures free; a free account unlocks up to 5 and keeps them in your dashboard.

What the sim shows

An ideal spring (k = 40 N/m, unloaded length 60 mm) hangs from a clamp. Each 50 g mass adds 0.49 N of weight (g = 9.81 N/kg) and stretches the spring by the same 12.3 mm, so extension is proportional to force: F = kx. Six masses and the hanger (350 g) stretch it 85.8 mm, still inside the limit of proportionality. The rule reads the spring's length from its top: the unloaded spring reaches the 6.0 cm line, and extension = stretched length − original length (here measured from the unloaded spring, so the 50 g hanger already stretches it 12.3 mm). The load bounces with the spring's own period, T = 2π√(m/k), before it settles. The spring's own mass is ignored.

  • Pointer: marks the spring's length on the rule (extension = new reading − 6.0 cm)
  • Slotted masses, 50 g each, on a 50 g hanger
  • Spring, k = 40 N/m

Use it in your lessons

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Free guide: 12 practicals as sims, and how to run one in a lesson →

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